Ported from Javascript. Credit goes to the original author of the Javascript (the script is quite widespread but I've never seen those using the script write the proper credit). Below is the code:
#!/usr/bin/env python
import math
def intPart(floatNum):
if floatNum < -0.0000001: return math.ceil(floatNum - 0.0000001)
return math.floor(floatNum + 0.0000001)
def Gregorian2Hijri(yr, mth, day):
if ((yr > 1582) or ((yr == 1582) and (mth > 10)) or \
((yr == 1582) and (mth == 10) and (day > 14))):
jd1 = intPart((1461 * (yr + 4800 + \
intPart((mth - 14) / 12.0))) / 4)
jd2 = intPart((367 * (mth - 2 - 12 * \
(intPart((mth - 14) / 12.0)))) / 12)
jd3 = intPart((3 * (intPart((yr + 4900 + \
intPart((mth - 14) / 12.0)) / 100))) / 4)
jd = jd1 + jd2 - jd3 + day - 32075
else:
jd1 = intPart((7 * (yr + 5001 + \
intPart((mth - 9) / 7.0))) / 4)
jd2 = intPart((275 * mth) / 9.0)
jd = 367 * yr - jd1 + jd2 + day + 1729777
l = jd - 1948440 + 10632
n = intPart((l - 1) /10631.0)
l = l - 10631 * n + 354
j1 = (intPart((10985 - l) / 5316.0)) * (intPart((50 * l) / 17719.0))
j2 = (intPart(l / 5670.0)) * (intPart((43 * l) / 15238.0))
j = j1 + j2
l1 = (intPart((30 - j) / 15.0)) * (intPart((17719 * j) / 50.0))
l2 = (intPart(j / 16.0)) * (intPart((15238 * j) / 43.0))
l = l - l1 - l2 + 29
m = intPart((24 * l) / 709.0)
d = l - intPart((709 * m) / 24.0)
y = 30 * n + j - 30
return y, m, d
def Hijri2Gregorian(yr, mth, day):
jd1 = intPart((11 * yr + 3) / 30.0)
jd2 = intPart((mth - 1) / 2.0)
jd = jd1 + 354 * yr + 30 * mth - jd2 + day + 1948440 - 385
if jd > 2299160:
l = jd + 68569
n = intPart((4 * l) / 146097.0)
l = l - intPart((146097 * n + 3) / 4.0)
i = intPart((4000 * (l + 1)) / 1461001.0)
l = l - intPart((1461 * i) / 4.0) + 31
j = intPart((80 * l) / 2447.0)
d = l - intPart((2447 * j) / 80.0)
l = intPart(j / 11.0)
m = j + 2 - 12 * l
y = 100 * (n - 49) + i + l
else:
j = jd + 1402
k = intPart((j - 1) / 1461.0)
l = j - 1461 * k
n = intPart((l - 1) / 365.0) - intPart(l / 1461.0)
i = l - 365 * n + 30
j = intPart((80 * i) / 2447.0)
d = i - intPart((2447 * j) / 80.0)
i = intPart(j / 11.0)
m = j + 2 - 12 * i
y = 4 * k + n + i - 4716
return y, m, d
Usage:# Convert from Gregorian to Hijri
print Gregorian2Hijri(1972, 12, 9)
print Gregorian2Hijri(2008, 1, 8)
# Convert from Hijri to Gregorian
print Hijri2Gregorian(1392, 11, 3)
print Hijri2Gregorian(1428, 12, 29)
