Python: Gregorian date to Hijri date conversion and vice versa

Ported from Javascript. Credit goes to the original author of the Javascript (the script is quite widespread but I've never seen those using the script write the proper credit). Below is the code:

#!/usr/bin/env python

import math

def intPart(floatNum):
    if floatNum < -0.0000001: return math.ceil(floatNum - 0.0000001)
    return math.floor(floatNum + 0.0000001)

def Gregorian2Hijri(yr, mth, day):
    if ((yr > 1582) or ((yr == 1582) and (mth > 10)) or \
        ((yr == 1582) and (mth == 10) and (day > 14))):
       jd1 = intPart((1461 * (yr + 4800 + \
                          intPart((mth - 14) / 12.0))) / 4)
       jd2 = intPart((367 * (mth - 2 - 12 * \
                         (intPart((mth - 14) / 12.0)))) / 12)
       jd3 = intPart((3 * (intPart((yr + 4900 + \
                          intPart((mth - 14) / 12.0)) / 100))) / 4)
       jd = jd1 + jd2 - jd3 + day - 32075
    else:
       jd1 = intPart((7 * (yr + 5001 + \
                          intPart((mth - 9) / 7.0))) / 4)
       jd2 = intPart((275 * mth) / 9.0)
       jd = 367 * yr - jd1 + jd2 + day + 1729777

    l = jd - 1948440 + 10632
    n = intPart((l - 1) /10631.0)
    l = l - 10631 * n + 354
    j1 = (intPart((10985 - l) / 5316.0)) * (intPart((50 * l) / 17719.0))
    j2 = (intPart(l / 5670.0)) * (intPart((43 * l) / 15238.0))
    j = j1 + j2
    l1 = (intPart((30 - j) / 15.0)) * (intPart((17719 * j) / 50.0))
    l2 = (intPart(j / 16.0)) * (intPart((15238 * j) / 43.0))
    l = l - l1 - l2 + 29
    m = intPart((24 * l) / 709.0)
    d = l - intPart((709 * m) / 24.0)
    y = 30 * n + j - 30

    return y, m, d

def Hijri2Gregorian(yr, mth, day):
    jd1 = intPart((11 * yr + 3) / 30.0)
    jd2 = intPart((mth - 1) / 2.0)
    jd = jd1 + 354 * yr + 30 * mth - jd2 + day + 1948440 - 385

    if jd > 2299160:
       l = jd + 68569
       n = intPart((4 * l) / 146097.0)
       l = l - intPart((146097 * n + 3) / 4.0)
       i = intPart((4000 * (l + 1)) / 1461001.0)
       l = l - intPart((1461 * i) / 4.0) + 31
       j = intPart((80 * l) / 2447.0)
       d = l - intPart((2447 * j) / 80.0)
       l = intPart(j / 11.0)
       m = j + 2 - 12 * l
       y = 100 * (n - 49) + i + l
    else:
       j = jd + 1402
       k = intPart((j - 1) / 1461.0)
       l = j - 1461 * k
       n = intPart((l - 1) / 365.0) - intPart(l / 1461.0)
       i = l - 365 * n + 30
       j = intPart((80 * i) / 2447.0)
       d = i - intPart((2447 * j) / 80.0)
       i = intPart(j / 11.0)
       m = j + 2 - 12 * i
       y = 4 * k + n + i - 4716

    return y, m, d

Usage:

# Convert from Gregorian to Hijri
print Gregorian2Hijri(1972, 12, 9)
print Gregorian2Hijri(2008, 1, 8)

# Convert from Hijri to Gregorian
print Hijri2Gregorian(1392, 11, 3)
print Hijri2Gregorian(1428, 12, 29)